Can You Solve This Math Olympiad Riddle for Kids?

 

🧠 Introduction

Math Olympiad problems aren’t just about numbers — they’re about thinking creatively.
Here’s a fun Olympiad-style puzzle for elementary students that tests reasoning, logic, and number sense. See if you can solve it before peeking at the solution!


❓ The Problem

Three siblings have whole-number ages.
The product of their ages is 36, and the sum of their ages is 13.

Can you find out how old the siblings are?

(Bonus: If there’s more than one possible answer, what extra clue might help you decide?)


🧩 Step-by-Step Solution

Step 1: Find all possible triples of ages

We’re looking for whole numbers a,b,ca, b, c such that

a×b×c=36.a \times b \times c = 36.

The prime factorization of 36 is 2×2×3×3.
Let’s group them into triples (order doesn’t matter):

Possible AgesSum
1, 1, 3638
1, 2, 1821
1, 3, 1216
1, 4, 914
1, 6, 613
2, 2, 913
2, 3, 611
3, 3, 410

Step 2: Use the sum condition

We’re told the sum is 13, so there are two possibilities:

  • (1, 6, 6)

  • (2, 2, 9)


Step 3: Use logic to break the tie

If you were told, “The oldest sibling loves chess,” what would that mean?

  • In (1, 6, 6), there are two oldest siblings (the twins, both 6).

  • In (2, 2, 9), there is one unique oldest sibling (the 9-year-old).

So the final answer must be: 2, 2, 9


Final Answer

The siblings are 2 years, 2 years, and 9 years old.


💡 Teaching Tip (for educators or parents)

This puzzle is great for:

  • practicing factors and multiplication,

  • introducing systematic listing, and

  • encouraging logical reasoning.

Try modifying the product (e.g. 24, 48, or 60) to create new challenges!


🏁 Conclusion

Math Olympiad problems like this show that logic and creativity are just as important as calculation. Encourage students to think about patterns and test their ideas — that’s what real problem-solving is all about!